What is (x^2+3x-4)/(x^2+6x+8) ?

The solution to (x^2+3x-4)/(x^2+6x+8) is (x-1)/(x+2)

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simplify (x^2+3x-4)/(x^2+6x+8)

simplify

\frac{x ^{2} + 3 x - 4}{x ^{2} + 6 x + 8}

\frac{x - 1}{x + 2}

Solution steps

\frac{x ^{2} + 3 x - 4}{x ^{2} + 6 x + 8}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x - 1 ) ( x + 4 )}{x ^{2} + 6 x + 8}

Factor

x^{2} + 6 x + 8 : (x + 2) (x + 4)

= \frac{( x - 1 ) ( x + 4 )}{( x + 2 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{x - 1}{x + 2}

lo g_{3} (\frac{1}{3 ^{2}})

\frac{4 a + 8 b}{12}

(2 x^{3}) (- 5 x^{2})

\frac{x ^{2} + 3 x - 28}{x ^{2} + 14 x + 49}

What is (x^2+3x-4)/(x^2+6x+8) ?
The solution to (x^2+3x-4)/(x^2+6x+8) is (x-1)/(x+2)