What is (32x^{-35}y^{-25})^{-4/5} ?

The solution to (32x^{-35}y^{-25})^{-4/5} is (x^{28}y^{20})/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (32x^{-35}y^{-25})^{-4/5}

simplify

(32 x^{- 35} y^{- 25})^{- \frac{4}{5}}

\frac{x ^{28} y ^{20}}{16}

Solution steps

(32 x^{- 35} y^{- 25})^{- \frac{4}{5}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(32 x^{- 35} y^{- 25})^{- \frac{4}{5}} = \frac{1}{( 32 x ^{- 35} y ^{- 25} ) ^{\frac{4}{5}}}

= \frac{1}{( 32 x ^{- 35} y ^{- 25} ) ^{\frac{4}{5}}}

Simplify

(32 x^{- 35} y^{- 25})^{\frac{4}{5}} : \frac{16}{x ^{28} y ^{20}}

= \frac{1}{\frac{16}{x ^{28} y ^{20}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{28} y ^{20}}{16}

\frac{3 + 1}{2}

0.5 \times 100

- 2 (x + h)^{2}

1.0 3^{4}

\frac{x ^{2} + 14 x + 48}{x ^{2} - 36}

What is (32x^{-35}y^{-25})^{-4/5} ?
The solution to (32x^{-35}y^{-25})^{-4/5} is (x^{28}y^{20})/(16)