What is (z+2)^2-5(z+2) ?

The solution to (z+2)^2-5(z+2) is z^2-z-6

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simplify (z+2)^2-5(z+2)

simplify

(z + 2)^{2} - 5 (z + 2)

z^{2} - z - 6

Solution steps

(z + 2)^{2} - 5 (z + 2)

Expand

(z + 2)^{2} : z^{2} + 4 z + 4

= z^{2} + 4 z + 4 - 5 (z + 2)

Expand

- 5 (z + 2) : - 5 z - 10

= z^{2} + 4 z + 4 - 5 z - 10

Group like terms

= z^{2} + 4 z - 5 z + 4 - 10

Add similar elements:

4 z - 5 z = - z

= z^{2} - z + 4 - 10

Subtract the numbers:

4 - 10 = - 6

= z^{2} - z - 6

\frac{2 ^{2} 2 ^{7}}{2 ^{3}}

- 11 - 5

- 11 - 9

\frac{1}{5 - 3}

\frac{5}{2 x} + \frac{7}{x}