What is (((4x^2y^3)^0)/(-3x^{-1)y^2})^3 ?

The solution to (((4x^2y^3)^0)/(-3x^{-1)y^2})^3 is -(x^3)/(27y^6)

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simplify (((4x^2y^3)^0)/(-3x^{-1)y^2})^3

simplify

(\frac{( 4 x ^{2} y ^{3} ) ^{0}}{- 3 x ^{- 1} y ^{2}})^{3}

- \frac{x ^{3}}{27 y ^{6}}

Solution steps

(\frac{( 4 x ^{2} y ^{3} ) ^{0}}{- 3 x ^{- 1} y ^{2}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( ( 4 x ^{2} y ^{3} ) ^{0} ) ^{3}}{( - 3 x ^{- 1} y ^{2} ) ^{3}}

Simplify

((4 x^{2} y^{3})^{0})^{3} : 1

= \frac{1}{( - 3 x ^{- 1} y ^{2} ) ^{3}}

Simplify

(- 3 x^{- 1} y^{2})^{3} : - \frac{27 y ^{6}}{x ^{3}}

= \frac{1}{- \frac{27 y ^{6}}{x ^{3}}}

Simplify

\frac{1}{- \frac{27 y ^{6}}{x ^{3}}} : - \frac{x ^{3}}{27 y ^{6}}

= - \frac{x ^{3}}{27 y ^{6}}

\frac{9}{20} + \frac{3}{4}

(4.18 - 3.1) \cdot 0.5 \cdot 0.3

ln (\frac{x}{x - 8}) + ln (\frac{x + 8}{x}) - ln (x^{2} - 64)

- 3 + (- 5)

\frac{10}{2 i}

What is (((4x^2y^3)^0)/(-3x^{-1)y^2})^3 ?
The solution to (((4x^2y^3)^0)/(-3x^{-1)y^2})^3 is -(x^3)/(27y^6)