What is [(\sqrt[3]{3})^{-2}]^6 ?

The solution to [(\sqrt[3]{3})^{-2}]^6 is 1/81

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simplify [(\sqrt[3]{3})^{-2}]^6

simplify

\frac{1}{81}

Decimal Notation

0.01234 \dots

Solution steps

Apply exponent rule:

(a^{b})^{c} = a^{b c}, a \geq 0

Multiply the numbers:

2 \cdot 6 = 12

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{3 ^{4}}

3^{4} = 81

= \frac{1}{81}

(x + 3) (3 x + 3)

- 3 x^{2} y^{5} z^{2} x - 2 y^{2} z^{2} x^{3} y - 2 z^{5} x^{2} y z^{3}

2 a^{2} - a - 3

16 - 9

\frac{12 x ^{3} + 7 x ^{2} + 9 x + 2}{4 x + 1}