What is (3x^3+4x^2-5x-2)/(x+2) ?

The solution to (3x^3+4x^2-5x-2)/(x+2) is (x-1)(3x+1)

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simplify (3x^3+4x^2-5x-2)/(x+2)

simplify

\frac{3 x ^{3} + 4 x ^{2} - 5 x - 2}{x + 2}

(x - 1) (3 x + 1)

Solution steps

\frac{3 x ^{3} + 4 x ^{2} - 5 x - 2}{x + 2}

Use the rational root theorem

= \frac{( x - 1 ) \frac{3 x ^{3} + 4 x ^{2} - 5 x - 2}{x - 1}}{x + 2}

\frac{3 x ^{3} + 4 x ^{2} - 5 x - 2}{x - 1} = 3 x^{2} + 7 x + 2

= \frac{( x - 1 ) ( 3 x ^{2} + 7 x + 2 )}{x + 2}

Factor

3 x^{2} + 7 x + 2 : (3 x + 1) (x + 2)

= \frac{( x - 1 ) ( 3 x + 1 ) ( x + 2 )}{x + 2}

Cancel the common factor:

x + 2

= (x - 1) (3 x + 1)

\frac{5}{6} - \frac{6}{5}

\frac{3}{12}

(2 w - 3)^{- 2}

i^{200}

- 4 \cdot - 4

What is (3x^3+4x^2-5x-2)/(x+2) ?
The solution to (3x^3+4x^2-5x-2)/(x+2) is (x-1)(3x+1)