What is (7w^8y^3)/(2yz) ?

The solution to (7w^8y^3)/(2yz) is (7w^8y^2)/(2z)

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simplify (7w^8y^3)/(2yz)

simplify

\frac{7 w ^{8} y ^{3}}{2 yz}

\frac{7 w ^{8} y ^{2}}{2 z}

Solution steps

\frac{7 w ^{8} y ^{3}}{2 yz}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{y ^{3}}{y ^{1}} = y^{3 - 1}

= \frac{7 w ^{8} y ^{3 - 1}}{2 z}

Subtract the numbers:

3 - 1 = 2

= \frac{7 w ^{8} y ^{2}}{2 z}

\frac{3 r ^{5} s t ^{7}}{- 6 rs t ^{3}}

x^{3} y^{5} - x^{4} y

\frac{9}{25} a^{2} - \frac{49}{36} b^{2}

(x - a) (x + a)

\frac{15 - \frac{2}{x}}{\frac{x}{5} + 4}