What is (2x^3+16x^2+24x)/(x^2-x-6) ?

The solution to (2x^3+16x^2+24x)/(x^2-x-6) is (2x(x+6))/(x-3)

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simplify (2x^3+16x^2+24x)/(x^2-x-6)

simplify

\frac{2 x ^{3} + 16 x ^{2} + 24 x}{x ^{2} - x - 6}

\frac{2 x ( x + 6 )}{x - 3}

Solution steps

\frac{2 x ^{3} + 16 x ^{2} + 24 x}{x ^{2} - x - 6}

Factor

2 x^{3} + 16 x^{2} + 24 x : 2 x (x + 2) (x + 6)

= \frac{2 x ( x + 2 ) ( x + 6 )}{x ^{2} - x - 6}

Factor

x^{2} - x - 6 : (x + 2) (x - 3)

= \frac{2 x ( x + 2 ) ( x + 6 )}{( x + 2 ) ( x - 3 )}

Cancel the common factor:

x + 2

= \frac{2 x ( x + 6 )}{x - 3}

\frac{17 x ^{3} y ^{4} z ^{6}}{34 x ^{7} y ^{8} z ^{10}}

\frac{2}{3} + \frac{7}{6}

3 x^{3}

- x^{2} - 9

\frac{2}{14} + \frac{- 1}{6} + \frac{11}{21} + \frac{- 8}{3}

What is (2x^3+16x^2+24x)/(x^2-x-6) ?
The solution to (2x^3+16x^2+24x)/(x^2-x-6) is (2x(x+6))/(x-3)