What are the solutions to the equation 2w^2+w+1=0 ?

The solutions to the equation 2w^2+w+1=0 are w=-1/4+i(sqrt(7))/4 ,w=-1/4-i(sqrt(7))/4

Find the zeros of 2w^2+w+1=0

The zeros of 2w^2+w+1=0 are w=-1/4+i(sqrt(7))/4 ,w=-1/4-i(sqrt(7))/4

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2 w^{2} + w + 1 = 0

w = - \frac{1}{4} + i \frac{7}{4}, w = - \frac{1}{4} - i \frac{7}{4}

Solution steps

2 w^{2} + w + 1 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 1 : 7 i

w_{1, 2} = \frac{- 1 \pm 7 i}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 1 + 7 i}{2 \cdot 2}, w_{2} = \frac{- 1 - 7 i}{2 \cdot 2}

w = \frac{- 1 + 7 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{7}{4}

w = \frac{- 1 - 7 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

w = - \frac{1}{4} + i \frac{7}{4}, w = - \frac{1}{4} - i \frac{7}{4}

\frac{5}{6} \cdot 7

2 x^{2} + 4 x + 1 = 0

2^{2^{3}}

(\frac{11}{10})^{2}

18 x^{3} - 9 x^{2} - 2 x + 1 < 0

What are the solutions to the equation 2w^2+w+1=0 ?
The solutions to the equation 2w^2+w+1=0 are w=-1/4+i(sqrt(7))/4 ,w=-1/4-i(sqrt(7))/4
Find the zeros of 2w^2+w+1=0
The zeros of 2w^2+w+1=0 are w=-1/4+i(sqrt(7))/4 ,w=-1/4-i(sqrt(7))/4