What is (x^2+x-6)/(x^2-5x+6)*(x^2-2x-3)/(x^2-4x-5) ?

The solution to (x^2+x-6)/(x^2-5x+6)*(x^2-2x-3)/(x^2-4x-5) is (x+3)/(x-5)

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simplify (x^2+x-6)/(x^2-5x+6)*(x^2-2x-3)/(x^2-4x-5)

simplify

\frac{x ^{2} + x - 6}{x ^{2} - 5 x + 6} \cdot \frac{x ^{2} - 2 x - 3}{x ^{2} - 4 x - 5}

\frac{x + 3}{x - 5}

Solution steps

\frac{x ^{2} + x - 6}{x ^{2} - 5 x + 6} \cdot \frac{x ^{2} - 2 x - 3}{x ^{2} - 4 x - 5}

Cancel

\frac{x ^{2} + x - 6}{x ^{2} - 5 x + 6} : \frac{x + 3}{x - 3}

= \frac{x + 3}{x - 3} \cdot \frac{x ^{2} - 2 x - 3}{x ^{2} - 4 x - 5}

Cancel

\frac{x ^{2} - 2 x - 3}{x ^{2} - 4 x - 5} : \frac{x - 3}{x - 5}

= \frac{x + 3}{x - 3} \cdot \frac{x - 3}{x - 5}

Cross-cancel common factor:

x - 3

= \frac{x + 3}{x - 5}

\frac{4 x - 16}{x} \cdot \frac{x ^{2} - 11 x + 24}{x ^{2} - 7 x + 12}

lo g_{4} (1 6^{5})

32 x^{2} y^{4}

(9 + 5 i)^{2}

1 + \frac{1}{1 + \frac{1}{1 + \frac{1}{1 + \frac{1}{x}}}}

What is (x^2+x-6)/(x^2-5x+6)*(x^2-2x-3)/(x^2-4x-5) ?
The solution to (x^2+x-6)/(x^2-5x+6)*(x^2-2x-3)/(x^2-4x-5) is (x+3)/(x-5)