What is expand (x-2)(x-4)(x-5) ?

The solution to expand (x-2)(x-4)(x-5) is x^3-11x^2+38x-40

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x-2)(x-4)(x-5)

expand

(x - 2) (x - 4) (x - 5)

x^{3} - 11 x^{2} + 38 x - 40

Solution steps

(x - 2) (x - 4) (x - 5)

Expand

(x - 2) (x - 4) (x - 5) : (x^{2} - 6 x + 8) (x - 5)

= (x^{2} - 6 x + 8) (x - 5)

Distribute parentheses

= x^{2} x + x^{2} (- 5) - 6 xx - 6 x (- 5) + 8 x + 8 (- 5)

Simplify

x^{2} x + x^{2} (- 5) - 6 xx - 6 x (- 5) + 8 x + 8 (- 5) : x^{3} - 11 x^{2} + 38 x - 40

= x^{3} - 11 x^{2} + 38 x - 40

\frac{18}{27 x + 27}

(9 c^{5} m^{9} p^{2}) (- \frac{1}{3} c^{6} m)

(\times + 2)^{2}

- 2 \times 7

8 \cdot 32

What is expand (x-2)(x-4)(x-5) ?
The solution to expand (x-2)(x-4)(x-5) is x^3-11x^2+38x-40