What is (2x^3+4x^2-5)-(4x^3-x^2+3x+12) ?

The solution to (2x^3+4x^2-5)-(4x^3-x^2+3x+12) is -2x^3+5x^2-3x-17

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simplify (2x^3+4x^2-5)-(4x^3-x^2+3x+12)

simplify

(2 x^{3} + 4 x^{2} - 5) - (4 x^{3} - x^{2} + 3 x + 12)

- 2 x^{3} + 5 x^{2} - 3 x - 17

Solution steps

(2 x^{3} + 4 x^{2} - 5) - (4 x^{3} - x^{2} + 3 x + 12)

Apply rule:

(a) = a

(2 x^{3} + 4 x^{2} - 5) = 2 x^{3} + 4 x^{2} - 5

= 2 x^{3} + 4 x^{2} - 5 - (4 x^{3} - x^{2} + 3 x + 12)

Apply the distributive law:

- (a - b) = - a + b

- (4 x^{3} - x^{2} + 3 x + 12) = - 4 x^{3} + x^{2} - 3 x - 12

= 2 x^{3} + 4 x^{2} - 5 - 4 x^{3} + x^{2} - 3 x - 12

Group like terms

= 2 x^{3} - 4 x^{3} + 4 x^{2} + x^{2} - 3 x - 5 - 12

Add similar elements:

2 x^{3} - 4 x^{3} = - 2 x^{3}

= - 2 x^{3} + 4 x^{2} + x^{2} - 3 x - 5 - 12

Add similar elements:

4 x^{2} + x^{2} = 5 x^{2}

= - 2 x^{3} + 5 x^{2} - 3 x - 5 - 12

Subtract the numbers:

- 5 - 12 = - 17

= - 2 x^{3} + 5 x^{2} - 3 x - 17

(2 x^{4}) (3 x^{6}) (- 2 x)

\frac{2}{3}

(6 + x) (6 - x)

(8 x - 3)^{2}

\frac{v ^{3} + 11 v ^{2} + 18 v}{v ^{2} + v - 2}

What is (2x^3+4x^2-5)-(4x^3-x^2+3x+12) ?
The solution to (2x^3+4x^2-5)-(4x^3-x^2+3x+12) is -2x^3+5x^2-3x-17