What is (2x^3-9x^2+13x-6)/(2x-3) ?

The solution to (2x^3-9x^2+13x-6)/(2x-3) is (x-1)(x-2)

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simplify (2x^3-9x^2+13x-6)/(2x-3)

simplify

\frac{2 x ^{3} - 9 x ^{2} + 13 x - 6}{2 x - 3}

(x - 1) (x - 2)

Solution steps

\frac{2 x ^{3} - 9 x ^{2} + 13 x - 6}{2 x - 3}

Use the rational root theorem

= \frac{( x - 1 ) \frac{2 x ^{3} - 9 x ^{2} + 13 x - 6}{x - 1}}{2 x - 3}

\frac{2 x ^{3} - 9 x ^{2} + 13 x - 6}{x - 1} = 2 x^{2} - 7 x + 6

= \frac{( x - 1 ) ( 2 x ^{2} - 7 x + 6 )}{2 x - 3}

Factor

2 x^{2} - 7 x + 6 : (2 x - 3) (x - 2)

= \frac{( x - 1 ) ( 2 x - 3 ) ( x - 2 )}{2 x - 3}

Cancel the common factor:

2 x - 3

= (x - 1) (x - 2)

\frac{20 !}{17 !}

e^{l n (x)}

\frac{500}{100}

(- 1 + 5 i) + (- 2 - 3 i)

What is (2x^3-9x^2+13x-6)/(2x-3) ?
The solution to (2x^3-9x^2+13x-6)/(2x-3) is (x-1)(x-2)