What is factor 3x^3-4x^2-5x+2 ?

The solution to factor 3x^3-4x^2-5x+2 is (x+1)(3x-1)(x-2)

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factor 3x^3-4x^2-5x+2

factor

3 x^{3} - 4 x^{2} - 5 x + 2

(x + 1) (3 x - 1) (x - 2)

Solution steps

3 x^{3} - 4 x^{2} - 5 x + 2

Use the rational root theorem

= (x + 1) \frac{3 x ^{3} - 4 x ^{2} - 5 x + 2}{x + 1}

\frac{3 x ^{3} - 4 x ^{2} - 5 x + 2}{x + 1} = 3 x^{2} - 7 x + 2

= (x + 1) (3 x^{2} - 7 x + 2)

Factor

3 x^{2} - 7 x + 2 : (3 x - 1) (x - 2)

= (x + 1) (3 x - 1) (x - 2)

\frac{\frac{3}{4} + \frac{1}{\frac{3}{4}}}{\frac{1}{\frac{3}{4}} - \frac{3}{4}}

\frac{d}{12} \cdot \frac{40}{d}

4 \frac{1}{2} \div \frac{1}{4}

\frac{1}{10} - \frac{1}{2}

(\frac{x}{2})^{4}

What is factor 3x^3-4x^2-5x+2 ?
The solution to factor 3x^3-4x^2-5x+2 is (x+1)(3x-1)(x-2)