What is ((x^3-8x^2+17x-10))/((x-5)) ?

The solution to ((x^3-8x^2+17x-10))/((x-5)) is (x-1)(x-2)

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simplify ((x^3-8x^2+17x-10))/((x-5))

simplify

\frac{( x ^{3} - 8 x ^{2} + 17 x - 10 )}{( x - 5 )}

(x - 1) (x - 2)

Solution steps

\frac{x ^{3} - 8 x ^{2} + 17 x - 10}{x - 5}

Use the rational root theorem

= \frac{( x - 1 ) \frac{x ^{3} - 8 x ^{2} + 17 x - 10}{x - 1}}{x - 5}

\frac{x ^{3} - 8 x ^{2} + 17 x - 10}{x - 1} = x^{2} - 7 x + 10

= \frac{( x - 1 ) ( x ^{2} - 7 x + 10 )}{x - 5}

Factor

x^{2} - 7 x + 10 : (x - 2) (x - 5)

= \frac{( x - 1 ) ( x - 2 ) ( x - 5 )}{x - 5}

Cancel the common factor:

x - 5

= (x - 1) (x - 2)

2 x (2 x - x)

\frac{3 a - 2 b}{3 a - 2 b}

13 \frac{π}{12}

(a^{- 1} \cdot a^{- 2})^{- 1}

\frac{2}{5} \times 2

What is ((x^3-8x^2+17x-10))/((x-5)) ?
The solution to ((x^3-8x^2+17x-10))/((x-5)) is (x-1)(x-2)