What is log_{10}(50)+log_{10}(2) ?

The solution to log_{10}(50)+log_{10}(2) is 2

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simplify log_{10}(50)+log_{10}(2)

simplify

lo g_{10} (50) + lo g_{10} (2)

2

Solution steps

lo g_{10} (50) + lo g_{10} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (50) + lo g_{10} (2) = lo g_{10} (50 \cdot 2)

= lo g_{10} (50 \cdot 2)

Multiply the numbers:

50 \cdot 2 = 100

= lo g_{10} (100)

Factor the number:

100 = 1 0^{2}

= lo g_{10} (1 0^{2})

Apply log rule:

lo g_{a} (a^{b}) = b

= 2

\frac{x ^{2} + 3 x - 10}{6 x ^{2} - 18 x} \cdot \frac{6 x ^{2} + 24 x - 126}{x ^{2} + 12 x + 35}

2 x^{3} - 3 x + 1

2 x (x + 5)

\frac{( 2 h ^{4} ) ^{5}}{6 h ^{6}}

\frac{x ^{\frac{5}{3}}}{\frac{5}{3}}

What is log_{10}(50)+log_{10}(2) ?
The solution to log_{10}(50)+log_{10}(2) is 2