What is (-18a^7b^3+9a^4b^2-63a^2b)/(9ab) ?

The solution to (-18a^7b^3+9a^4b^2-63a^2b)/(9ab) is -a(2a^5b^2-a^2b+7)

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simplify (-18a^7b^3+9a^4b^2-63a^2b)/(9ab)

simplify

\frac{- 18 a ^{7} b ^{3} + 9 a ^{4} b ^{2} - 63 a ^{2} b}{9 ab}

- a (2 a^{5} b^{2} - a^{2} b + 7)

Solution steps

\frac{- 18 a ^{7} b ^{3} + 9 a ^{4} b ^{2} - 63 a ^{2} b}{9 ab}

Factor

- 18 a^{7} b^{3} + 9 a^{4} b^{2} - 63 a^{2} b : - 9 a^{2} b (2 a^{5} b^{2} - a^{2} b + 7)

= \frac{- 9 a ^{2} b ( 2 a ^{5} b ^{2} - a ^{2} b + 7 )}{9 ab}

Cancel the common factor:

9

= \frac{- a ^{2} b ( 2 a ^{5} b ^{2} - a ^{2} b + 7 )}{ab}

Cancel the common factor:

b

= \frac{- a ^{2} ( 2 a ^{5} b ^{2} - a ^{2} b + 7 )}{a}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

a^{2} = aa

= \frac{- aa ( 2 a ^{5} b ^{2} - a ^{2} b + 7 )}{a}

Cancel the common factor:

a

= - a (2 a^{5} b^{2} - a^{2} b + 7)

\frac{1}{3} x = 2 - \frac{2}{3} x

0. 5^{4}

2 x - 1 \leq 3 - x

∣ - 25 x ∣ = 100

2 (2 x - 3) \leq 2 x - 7

What is (-18a^7b^3+9a^4b^2-63a^2b)/(9ab) ?
The solution to (-18a^7b^3+9a^4b^2-63a^2b)/(9ab) is -a(2a^5b^2-a^2b+7)