What is (7x^2+3x+4)-(2x^2+6x-5) ?

The solution to (7x^2+3x+4)-(2x^2+6x-5) is 5x^2-3x+9

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simplify (7x^2+3x+4)-(2x^2+6x-5)

simplify

(7 x^{2} + 3 x + 4) - (2 x^{2} + 6 x - 5)

5 x^{2} - 3 x + 9

Solution steps

(7 x^{2} + 3 x + 4) - (2 x^{2} + 6 x - 5)

Apply rule:

(a) = a

(7 x^{2} + 3 x + 4) = 7 x^{2} + 3 x + 4

= 7 x^{2} + 3 x + 4 - (2 x^{2} + 6 x - 5)

Apply the distributive law:

- (a + b) = - a - b

- (2 x^{2} + 6 x - 5) = - 2 x^{2} - 6 x + 5

= 7 x^{2} + 3 x + 4 - 2 x^{2} - 6 x + 5

Group like terms

= 7 x^{2} - 2 x^{2} + 3 x - 6 x + 4 + 5

Add similar elements:

7 x^{2} - 2 x^{2} = 5 x^{2}

= 5 x^{2} + 3 x - 6 x + 4 + 5

Add similar elements:

3 x - 6 x = - 3 x

= 5 x^{2} - 3 x + 4 + 5

Add the numbers:

4 + 5 = 9

= 5 x^{2} - 3 x + 9

(x - 2) (x - 3)

0.5 (- 8)^{2}

(x + 12) (x + 12)

(- 4 + 5 i) - (4 + 7 i)

- x^{3} + 5 x^{2} - 3 x - 9

What is (7x^2+3x+4)-(2x^2+6x-5) ?
The solution to (7x^2+3x+4)-(2x^2+6x-5) is 5x^2-3x+9