What is ((1+2^{(-3s)}+9^2-2s^3))/((s^2(s-2)^2)) ?

The solution to ((1+2^{(-3s)}+9^2-2s^3))/((s^2(s-2)^2)) is (-2^{1+3s}s^3+1+82*8^s)/(8^ss^2(s-2)^2)

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simplify ((1+2^{(-3s)}+9^2-2s^3))/((s^2(s-2)^2))

simplify

\frac{( 1 + 2 ^{(- 3 s)} + 9 ^{2} - 2 s ^{3} )}{( s ^{2} ( s - 2 ) ^{2} )}

\frac{- 2 ^{1 + 3 s} s ^{3} + 1 + 82 \cdot 8 ^{s}}{8 ^{s} s ^{2} ( s - 2 ) ^{2}}

Solution steps

\frac{1 + 2 ^{- 3 s} + 9 ^{2} - 2 s ^{3}}{s ^{2} ( s - 2 ) ^{2}}

Simplify

1 + 2^{- 3 s} + 9^{2} - 2 s^{3} : \frac{- 2 ^{1 + 3 s} s ^{3} + 1 + 82 \cdot 8 ^{s}}{8 ^{s}}

= \frac{\frac{- 2 ^{1 + 3 s} s ^{3} + 1 + 82 \cdot 8 ^{s}}{8 ^{s}}}{s ^{2} ( s - 2 ) ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{- 2 ^{1 + 3 s} s ^{3} + 1 + 82 \cdot 8 ^{s}}{8 ^{s} s ^{2} ( s - 2 ) ^{2}}

6 x^{2} - 2 x y + 3 x^{2}

\frac{7 m n ^{4} p ^{5}}{21 m ^{3} n p ^{7}}

(- 2 i) (5 i^{2}) (- 5 i)

\frac{1}{( \frac{1 - x}{x} ) + 1}

What is ((1+2^{(-3s)}+9^2-2s^3))/((s^2(s-2)^2)) ?
The solution to ((1+2^{(-3s)}+9^2-2s^3))/((s^2(s-2)^2)) is (-2^{1+3s}s^3+1+82*8^s)/(8^ss^2(s-2)^2)