What is (1/(x-1))/(1/(x^2+1)) ?

The solution to (1/(x-1))/(1/(x^2+1)) is (x^2+1)/(x-1)

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simplify (1/(x-1))/(1/(x^2+1))

simplify

\frac{\frac{1}{x - 1}}{\frac{1}{x ^{2} + 1}}

\frac{x ^{2} + 1}{x - 1}

Solution steps

\frac{\frac{1}{x - 1}}{\frac{1}{x ^{2} + 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{1 \cdot ( x ^{2} + 1 )}{( x - 1 ) \cdot 1}

Apply rule:

a \cdot 1 = a

= \frac{x ^{2} + 1}{x - 1}

\frac{\frac{4}{9} + \frac{5}{6}}{\frac{3}{5}}

\frac{x + 3}{x - 8} - \frac{x - 4}{x}

\frac{11 - 3}{11 + 3}

7 r + 14 s

(4 a b^{2} + 2 c) (- 2 a b^{2} + c)

What is (1/(x-1))/(1/(x^2+1)) ?
The solution to (1/(x-1))/(1/(x^2+1)) is (x^2+1)/(x-1)