What is (-7x^4+7x^2+6x-8)-(9x^2-9+3x^5) ?

The solution to (-7x^4+7x^2+6x-8)-(9x^2-9+3x^5) is -3x^5-7x^4-2x^2+6x+1

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simplify (-7x^4+7x^2+6x-8)-(9x^2-9+3x^5)

simplify

(- 7 x^{4} + 7 x^{2} + 6 x - 8) - (9 x^{2} - 9 + 3 x^{5})

- 3 x^{5} - 7 x^{4} - 2 x^{2} + 6 x + 1

Solution steps

(- 7 x^{4} + 7 x^{2} + 6 x - 8) - (9 x^{2} - 9 + 3 x^{5})

Apply rule:

(a) = a

(- 7 x^{4} + 7 x^{2} + 6 x - 8) = - 7 x^{4} + 7 x^{2} + 6 x - 8

= - 7 x^{4} + 7 x^{2} + 6 x - 8 - (9 x^{2} - 9 + 3 x^{5})

Apply the distributive law:

- (a - b) = - a + b

- (9 x^{2} - 9 + 3 x^{5}) = - 9 x^{2} + 9 - 3 x^{5}

= - 7 x^{4} + 7 x^{2} + 6 x - 8 - 9 x^{2} + 9 - 3 x^{5}

Group like terms

= - 3 x^{5} - 7 x^{4} + 7 x^{2} - 9 x^{2} + 6 x - 8 + 9

Add similar elements:

7 x^{2} - 9 x^{2} = - 2 x^{2}

= - 3 x^{5} - 7 x^{4} - 2 x^{2} + 6 x - 8 + 9

Add the numbers:

- 8 + 9 = 1

= - 3 x^{5} - 7 x^{4} - 2 x^{2} + 6 x + 1

\frac{x ^{2} + x - 2}{x - 1}

12 m^{2} - 4 mn - 8 n^{2}

5.98 \cdot 1 0^{24}

(2 + h)^{4}

8 x^{3} - 729

What is (-7x^4+7x^2+6x-8)-(9x^2-9+3x^5) ?
The solution to (-7x^4+7x^2+6x-8)-(9x^2-9+3x^5) is -3x^5-7x^4-2x^2+6x+1