What is (3x^2-3)/(4x^2+4x) ?

The solution to (3x^2-3)/(4x^2+4x) is (3(x-1))/(4x)

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simplify (3x^2-3)/(4x^2+4x)

simplify

\frac{3 x ^{2} - 3}{4 x ^{2} + 4 x}

\frac{3 ( x - 1 )}{4 x}

Solution steps

\frac{3 x ^{2} - 3}{4 x ^{2} + 4 x}

Factor

3 x^{2} - 3 : 3 (x + 1) (x - 1)

= \frac{3 ( x + 1 ) ( x - 1 )}{4 x ^{2} + 4 x}

Factor

4 x^{2} + 4 x : 4 x (x + 1)

= \frac{3 ( x + 1 ) ( x - 1 )}{4 x ( x + 1 )}

Cancel the common factor:

x + 1

= \frac{3 ( x - 1 )}{4 x}

(3 x)^{5}

[\frac{( 5 x y + 5 x ^{3} y )}{5 x}] + 5 y

\frac{7}{49}

19 2^{\frac{1}{3}}

488 + (87 - x)

What is (3x^2-3)/(4x^2+4x) ?
The solution to (3x^2-3)/(4x^2+4x) is (3(x-1))/(4x)