What is factor 2x^3+3x^2-5x-6 ?

The solution to factor 2x^3+3x^2-5x-6 is (x+1)(2x-3)(x+2)

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factor 2x^3+3x^2-5x-6

factor

2 x^{3} + 3 x^{2} - 5 x - 6

(x + 1) (2 x - 3) (x + 2)

Solution steps

2 x^{3} + 3 x^{2} - 5 x - 6

Use the rational root theorem

= (x + 1) \frac{2 x ^{3} + 3 x ^{2} - 5 x - 6}{x + 1}

\frac{2 x ^{3} + 3 x ^{2} - 5 x - 6}{x + 1} = 2 x^{2} + x - 6

= (x + 1) (2 x^{2} + x - 6)

Factor

2 x^{2} + x - 6 : (2 x - 3) (x + 2)

= (x + 1) (2 x - 3) (x + 2)

\frac{100}{120}

\frac{\frac{x + y}{6}}{\frac{x ^{2} - y ^{2}}{3}}

\frac{5}{2} \div \frac{5}{7}

3 \times 1 0^{- 4}

(s + 1 + i) (s + 1 - i)

What is factor 2x^3+3x^2-5x-6 ?
The solution to factor 2x^3+3x^2-5x-6 is (x+1)(2x-3)(x+2)