What is ((-4x^4+3x^2+12-11x^3))/((-x^2-2x+3)) ?

The solution to ((-4x^4+3x^2+12-11x^3))/((-x^2-2x+3)) is (4x^3+15x^2+12x+12)/(x+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((-4x^4+3x^2+12-11x^3))/((-x^2-2x+3))

simplify

\frac{( - 4 x ^{4} + 3 x ^{2} + 12 - 11 x ^{3} )}{( - x ^{2} - 2 x + 3 )}

\frac{4 x ^{3} + 15 x ^{2} + 12 x + 12}{x + 3}

Solution steps

\frac{- 4 x ^{4} + 3 x ^{2} + 12 - 11 x ^{3}}{- x ^{2} - 2 x + 3}

Factor

- 4 x^{4} + 3 x^{2} + 12 - 11 x^{3} : - (x - 1) (4 x^{3} + 15 x^{2} + 12 x + 12)

= \frac{- ( x - 1 ) ( 4 x ^{3} + 15 x ^{2} + 12 x + 12 )}{- x ^{2} - 2 x + 3}

Factor

- x^{2} - 2 x + 3 : - (x - 1) (x + 3)

= \frac{- ( x - 1 ) ( 4 x ^{3} + 15 x ^{2} + 12 x + 12 )}{- ( x - 1 ) ( x + 3 )}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{( x - 1 ) ( 4 x ^{3} + 15 x ^{2} + 12 x + 12 )}{( x - 1 ) ( x + 3 )}

Cancel the common factor:

x - 1

= \frac{4 x ^{3} + 15 x ^{2} + 12 x + 12}{x + 3}

x + x^{- 1}

(30)^{2}

\frac{1 + 0.95}{2}

\frac{3}{5} \cdot 150

6 x^{2} + 4 x

What is ((-4x^4+3x^2+12-11x^3))/((-x^2-2x+3)) ?
The solution to ((-4x^4+3x^2+12-11x^3))/((-x^2-2x+3)) is (4x^3+15x^2+12x+12)/(x+3)