What is expand (-3x^2y^3+2xy^2)^2 ?

The solution to expand (-3x^2y^3+2xy^2)^2 is 9x^4y^6-12x^3y^5+4x^2y^4

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expand (-3x^2y^3+2xy^2)^2

expand

(- 3 x^{2} y^{3} + 2 x y^{2})^{2}

9 x^{4} y^{6} - 12 x^{3} y^{5} + 4 x^{2} y^{4}

Solution steps

(- 3 x^{2} y^{3} + 2 x y^{2})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(- 3 x^{2} y^{3} + 2 x y^{2})^{2} = (- 3 x^{2} y^{3})^{2} + 2 (- 3 x^{2} y^{3}) \cdot 2 x y^{2} + (2 x y^{2})^{2}

= (- 3 x^{2} y^{3})^{2} + 2 (- 3 x^{2} y^{3}) \cdot 2 x y^{2} + (2 x y^{2})^{2}

Simplify

(- 3 x^{2} y^{3})^{2} + 2 (- 3 x^{2} y^{3}) \cdot 2 x y^{2} + (2 x y^{2})^{2} : 9 x^{4} y^{6} - 12 x^{3} y^{5} + 4 x^{2} y^{4}

= 9 x^{4} y^{6} - 12 x^{3} y^{5} + 4 x^{2} y^{4}

\frac{4}{5} n - 3 + \frac{7}{10} n

- 5.9 g - (- 10 h + 2.7)

i (2 + i)

\frac{sec ^{2} ( x ) - 1}{sec ( x ) - 1}

\frac{3}{14 x} + \frac{9}{10 x ^{2}}

What is expand (-3x^2y^3+2xy^2)^2 ?
The solution to expand (-3x^2y^3+2xy^2)^2 is 9x^4y^6-12x^3y^5+4x^2y^4