What is (4x(x^2-1)-2x^2*2x)/((x^2-1)^2) ?

The solution to (4x(x^2-1)-2x^2*2x)/((x^2-1)^2) is -(4x)/((x^2-1)^2)

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simplify (4x(x^2-1)-2x^2*2x)/((x^2-1)^2)

simplify

\frac{4 x ( x ^{2} - 1 ) - 2 x ^{2} \cdot 2 x}{( x ^{2} - 1 ) ^{2}}

- \frac{4 x}{( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{4 x ( x ^{2} - 1 ) - 2 x ^{2} \cdot 2 x}{( x ^{2} - 1 ) ^{2}}

Simplify

4 x (x^{2} - 1) - 2 x^{2} \cdot 2 x : - 4 x

= \frac{- 4 x}{( x ^{2} - 1 ) ^{2}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4 x}{( x ^{2} - 1 ) ^{2}}

\frac{10 a 0.1}{10}

ln (0.11)

x^{2} y^{3} + x^{3} y^{2}

(\frac{m ^{3}}{4 c ^{5}})^{- 4}

\frac{x ^{3} - 7 x - 6}{x + 1}

What is (4x(x^2-1)-2x^2*2x)/((x^2-1)^2) ?
The solution to (4x(x^2-1)-2x^2*2x)/((x^2-1)^2) is -(4x)/((x^2-1)^2)