What is (6h^{10}u^4)/((-2h^{-4)u^3)^3} ?

The solution to (6h^{10}u^4)/((-2h^{-4)u^3)^3} is -(3h^{22})/(4u^5)

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simplify (6h^{10}u^4)/((-2h^{-4)u^3)^3}

simplify

\frac{6 h ^{10} u ^{4}}{( - 2 h ^{- 4} u ^{3} ) ^{3}}

- \frac{3 h ^{22}}{4 u ^{5}}

Solution steps

\frac{6 h ^{10} u ^{4}}{( - 2 h ^{- 4} u ^{3} ) ^{3}}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2 h^{- 4} u^{3})^{3} = - (2 h^{- 4} u^{3})^{3}

= \frac{6 h ^{10} u ^{4}}{- ( 2 h ^{- 4} u ^{3} ) ^{3}}

Simplify

(2 h^{- 4} u^{3})^{3} : 2^{3} \cdot \frac{1}{h ^{12}} u^{9}

= \frac{6 h ^{10} u ^{4}}{- 2 ^{3} \cdot \frac{1}{h ^{12}} u ^{9}}

Factor the number:

6 = 2 \cdot 3

= \frac{2 \cdot 3 h ^{10} u ^{4}}{- 2 ^{3} \cdot \frac{1}{h ^{12}} u ^{9}}

\frac{2}{2 ^{3}} = \frac{1}{2 ^{2}}

= \frac{3 h ^{10} u ^{4}}{- 2 ^{2} \cdot \frac{1}{h ^{12}} u ^{9}}

Simplify

\frac{u ^{4}}{u ^{9}} : \frac{1}{u ^{5}}

= \frac{3 h ^{10}}{- 2 ^{2} \cdot \frac{1}{h ^{12}} u ^{5}}

Simplify

\frac{3 h ^{10}}{- 2 ^{2} \cdot \frac{1}{h ^{12}} u ^{5}} : - \frac{3 h ^{22}}{4 u ^{5}}

= - \frac{3 h ^{22}}{4 u ^{5}}

(1 + 2 x)^{4}

(3 - 2 x)^{2}

- 1 (2)

- 11 + 1

\frac{( 2 x + 7 ) - 7}{2}

What is (6h^{10}u^4)/((-2h^{-4)u^3)^3} ?
The solution to (6h^{10}u^4)/((-2h^{-4)u^3)^3} is -(3h^{22})/(4u^5)