What are the solutions to the equation (y+7)^2=16 ?

The solutions to the equation (y+7)^2=16 are y=-3,y=-11

Find the zeros of (y+7)^2=16

The zeros of (y+7)^2=16 are y=-3,y=-11

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(y + 7)^{2} = 16

y = - 3, y = - 11

Solution steps

(y + 7)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 7 = 16 : y = - 3

Solve

y + 7 = - 16 : y = - 11

The solutions to the quadratic equation are:

y = - 3, y = - 11

5 - \frac{x}{7} = 11

\frac{x + 1}{x - 2} \leq 2

4 x^{2} - 8 x - 21 = 0

\frac{4}{5 + i}

What are the solutions to the equation (y+7)^2=16 ?
The solutions to the equation (y+7)^2=16 are y=-3,y=-11
Find the zeros of (y+7)^2=16
The zeros of (y+7)^2=16 are y=-3,y=-11