What is (1/2+(sqrt(3))/2 i)^{2-3i} ?

The solution to (1/2+(sqrt(3))/2 i)^{2-3i} is ((1+sqrt(3)i)/2)^{2-3i}

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simplify (1/2+(sqrt(3))/2 i)^{2-3i}

simplify

(\frac{1}{2} + \frac{3}{2} i)^{2 - 3 i}

(\frac{1 + 3 i}{2})^{2 - 3 i}

Solution steps

(\frac{1}{2} + \frac{3}{2} i)^{2 - 3 i}

Multiply

\frac{3}{2} i : \frac{3 i}{2}

= (\frac{1}{2} + \frac{3 i}{2})^{2 - 3 i}

Combine the fractions

\frac{1}{2} + \frac{3 i}{2} : \frac{1 + 3 i}{2}

= (\frac{1 + 3 i}{2})^{2 - 3 i}

\frac{1}{15} - \frac{1}{3} - \frac{4}{5}

3 x^{4} + 4 x^{3}

s^{4} - 16

arctan (2 x) - \frac{x ^{2}}{5}

1 + 3.322 lo g_{10} (40)

What is (1/2+(sqrt(3))/2 i)^{2-3i} ?
The solution to (1/2+(sqrt(3))/2 i)^{2-3i} is ((1+sqrt(3)i)/2)^{2-3i}