What is the first d/(dI)(x^2In(x)) ?

The first d/(dI)(x^2In(x)) is nx^3

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d/(dI)(x^2In(x))

\frac{d}{d I} (x^{2} I n (x))

n x^{3}

Solution steps

\frac{d}{d I} (x^{2} I n (x))

Simplify

x^{2} I n (x) : n x^{3} I

= \frac{d}{d I} (n x^{3} I)

Treat

n, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= n x^{3} \frac{d I}{d I}

Apply the common derivative:

\frac{d I}{d I} = 1

= n x^{3} \cdot 1

Simplify

= n x^{3}

1^{2} + (- 1)^{2}

∣ 4 + 2 i ∣

\frac{3 5}{15}

- y + 3 y

- y + 2 y