What is 7/(3x^2-75)+3/(2x+10) ?

The solution to 7/(3x^2-75)+3/(2x+10) is (9x-31)/(6(x+5)(x-5))

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simplify 7/(3x^2-75)+3/(2x+10)

simplify

\frac{7}{3 x ^{2} - 75} + \frac{3}{2 x + 10}

\frac{9 x - 31}{6 ( x + 5 ) ( x - 5 )}

Solution steps

\frac{7}{3 x ^{2} - 75} + \frac{3}{2 x + 10}

Least Common Multiplier of

3 x^{2} - 75, 2 x + 10 : 6 (x + 5) (x - 5)

Adjust Fractions based on the LCM

= \frac{14}{6 ( x + 5 ) ( x - 5 )} + \frac{9 ( x - 5 )}{6 ( x + 5 ) ( x - 5 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{14 + 9 ( x - 5 )}{6 ( x + 5 ) ( x - 5 )}

Simplify

14 + 9 (x - 5) : 9 x - 31

= \frac{9 x - 31}{6 ( x + 5 ) ( x - 5 )}

3 x^{2} + 2 x^{3}

2 mn - 5 mn + 8 mn - 10 mn + 6 mn - 3 mn + mn

(m - 3 + 4 n) \cdot (- 8)

\frac{cos ^{2} ( x )}{cos ^{2} ( x )}

9 \div \frac{3}{4}

What is 7/(3x^2-75)+3/(2x+10) ?
The solution to 7/(3x^2-75)+3/(2x+10) is (9x-31)/(6(x+5)(x-5))