What is (3b^{-9})/((3b^{-4)c^{-3})^{-3}} ?

The solution to (3b^{-9})/((3b^{-4)c^{-3})^{-3}} is (81)/(b^{21)c^9}

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simplify (3b^{-9})/((3b^{-4)c^{-3})^{-3}}

simplify

\frac{3 b ^{- 9}}{( 3 b ^{- 4} c ^{- 3} ) ^{- 3}}

\frac{81}{b ^{21} c ^{9}}

Solution steps

\frac{3 b ^{- 9}}{( 3 b ^{- 4} c ^{- 3} ) ^{- 3}}

Simplify

(3 b^{- 4} c^{- 3})^{- 3} : 3^{- 3} b^{12} c^{9}

= \frac{3 b ^{- 9}}{3 ^{- 3} b ^{12} c ^{9}}

\frac{3}{3 ^{- 3}} = 3^{4}

= \frac{3 ^{4} b ^{- 9}}{b ^{12} c ^{9}}

Simplify

\frac{b ^{- 9}}{b ^{12}} : \frac{1}{b ^{21}}

= \frac{3 ^{4}}{b ^{21} c ^{9}}

3^{4} = 81

= \frac{81}{b ^{21} c ^{9}}

(\frac{1}{2} a^{2} + \frac{3}{6} b) (\frac{1}{2} a^{2} - \frac{3}{6} b)

\frac{15}{39}

lo g_{10} (A^{n})

5 x + 6 x y - 7 x + 3 y + 12 x - 9 y + 12 x y + 10 x y

49 (y - 4)^{2} - 9 (y + 2)^{2}

What is (3b^{-9})/((3b^{-4)c^{-3})^{-3}} ?
The solution to (3b^{-9})/((3b^{-4)c^{-3})^{-3}} is (81)/(b^{21)c^9}