What is ((n^2-16)/3)/(\frac{n+4){21}} ?

The solution to ((n^2-16)/3)/(\frac{n+4){21}} is 7n-28

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simplify ((n^2-16)/3)/(\frac{n+4){21}}

simplify

\frac{\frac{n ^{2} - 16}{3}}{\frac{n + 4}{21}}

7 n - 28

Solution steps

\frac{\frac{n ^{2} - 16}{3}}{\frac{n + 4}{21}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( n ^{2} - 16 ) \cdot 21}{3 ( n + 4 )}

Cancel

\frac{( n ^{2} - 16 ) \cdot 21}{3 ( n + 4 )} : (n - 4) \cdot 7

= (n - 4) \cdot 7

Expand

(n - 4) \cdot 7 : 7 n - 28

= 7 n - 28

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What is ((n^2-16)/3)/(\frac{n+4){21}} ?
The solution to ((n^2-16)/3)/(\frac{n+4){21}} is 7n-28