What is (x^2+3x-4)/(x^3-1) ?

The solution to (x^2+3x-4)/(x^3-1) is (x+4)/(x^2+x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x^2+3x-4)/(x^3-1)

simplify

\frac{x ^{2} + 3 x - 4}{x ^{3} - 1}

\frac{x + 4}{x ^{2} + x + 1}

Solution steps

\frac{x ^{2} + 3 x - 4}{x ^{3} - 1}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x - 1 ) ( x + 4 )}{x ^{3} - 1}

Factor

x^{3} - 1 : (x - 1) (x^{2} + x + 1)

= \frac{( x - 1 ) ( x + 4 )}{( x - 1 ) ( x ^{2} + x + 1 )}

Cancel the common factor:

x - 1

= \frac{x + 4}{x ^{2} + x + 1}

(\frac{25 x ^{4}}{4})^{- \frac{1}{2}}

\frac{x ^{2} + 6 x + 8}{x ^{2} + 7 x + 12}

(x^{4} + x^{2}) (x^{6} - 3 x^{3})

(7 x)^{0}

(2 x^{2} + y^{3})^{2}

What is (x^2+3x-4)/(x^3-1) ?
The solution to (x^2+3x-4)/(x^3-1) is (x+4)/(x^2+x+1)