What is (6x^2-3x-7)-(8x^2+7x+4) ?

The solution to (6x^2-3x-7)-(8x^2+7x+4) is -2x^2-10x-11

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simplify (6x^2-3x-7)-(8x^2+7x+4)

simplify

(6 x^{2} - 3 x - 7) - (8 x^{2} + 7 x + 4)

- 2 x^{2} - 10 x - 11

Solution steps

(6 x^{2} - 3 x - 7) - (8 x^{2} + 7 x + 4)

Apply rule:

(a) = a

(6 x^{2} - 3 x - 7) = 6 x^{2} - 3 x - 7

= 6 x^{2} - 3 x - 7 - (8 x^{2} + 7 x + 4)

Apply the distributive law:

- (a + b) = - a - b

- (8 x^{2} + 7 x + 4) = - 8 x^{2} - 7 x - 4

= 6 x^{2} - 3 x - 7 - 8 x^{2} - 7 x - 4

Group like terms

= 6 x^{2} - 8 x^{2} - 3 x - 7 x - 7 - 4

Add similar elements:

6 x^{2} - 8 x^{2} = - 2 x^{2}

= - 2 x^{2} - 3 x - 7 x - 7 - 4

Add similar elements:

- 3 x - 7 x = - 10 x

= - 2 x^{2} - 10 x - 7 - 4

Subtract the numbers:

- 7 - 4 = - 11

= - 2 x^{2} - 10 x - 11

\frac{π}{\frac{3}{2}}

(\frac{1}{4 x ^{3} y ^{4}}) (\frac{1}{3 x y ^{2}})

4 \cdot \frac{5}{4}

2.7

\frac{120}{20}

What is (6x^2-3x-7)-(8x^2+7x+4) ?
The solution to (6x^2-3x-7)-(8x^2+7x+4) is -2x^2-10x-11