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Popular >

|2k-1|<= 2

Solution

∣ 2 k - 1 ∣ \leq 2

Solution

- \frac{1}{2} \leq k \leq \frac{3}{2}

+2

Solution steps

∣ 2 k - 1 ∣ \leq 2

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 2 \leq 2 k - 1 \leq 2

2 k - 1 \geq - 2 and 2 k - 1 \leq 2

k \geq - \frac{1}{2} and k \leq \frac{3}{2}

Merge Overlapping Intervals

- \frac{1}{2} \leq k \leq \frac{3}{2}

Popular Examples

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x^{2} - 48 x + 576

4 x^{2} = 72

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4 x - 2 = x + 9

(0-1)^2+(y-(-2))^2=2^2

(0 - 1)^{2} + (y - (- 2))^{2} = 2^{2}

Frequently Asked Questions (FAQ)

What is |2k-1|<= 2 ?
The solution to |2k-1|<= 2 is -1/2 <= k<= 3/2