What is (2x^3+7x^2+10x+8)/(x+2) ?

The solution to (2x^3+7x^2+10x+8)/(x+2) is 2x^2+3x+4

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simplify (2x^3+7x^2+10x+8)/(x+2)

simplify

\frac{2 x ^{3} + 7 x ^{2} + 10 x + 8}{x + 2}

2 x^{2} + 3 x + 4

Solution steps

\frac{2 x ^{3} + 7 x ^{2} + 10 x + 8}{x + 2}

Factor

2 x^{3} + 7 x^{2} + 10 x + 8 : (x + 2) (2 x^{2} + 3 x + 4)

= \frac{( x + 2 ) ( 2 x ^{2} + 3 x + 4 )}{x + 2}

Cancel the common factor:

x + 2

= 2 x^{2} + 3 x + 4

(x + \frac{2}{3})^{2}

x^{9} + x^{6} + x^{3}

(2 cos (2 t))^{2}

(\frac{4}{5})^{3} \cdot (\frac{3}{10})^{- 2} \cdot (\frac{4}{3})^{- 4}

What is (2x^3+7x^2+10x+8)/(x+2) ?
The solution to (2x^3+7x^2+10x+8)/(x+2) is 2x^2+3x+4