What is (\sqrt[5]{xy^{-3}})x^{-1}y^{-2} ?

The solution to (\sqrt[5]{xy^{-3}})x^{-1}y^{-2} is 1/(\sqrt[5]{x^4)\sqrt[5]{y^3}y^2}

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simplify (\sqrt[5]{xy^{-3}})x^{-1}y^{-2}

simplify

Solution steps

Apply rule:

(a) = a

Simplify

Apply radical rule:

Simplify

x^{\frac{1}{5}} x^{- 1} : \frac{1}{x ^{\frac{4}{5}}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 2} = \frac{1}{y ^{2}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

Multiply the numbers:

1 \cdot 1 \cdot 1 = 1

(2 ab - 2 b^{2}) (\frac{a + b}{2})

(6 w - 11 w^{2}) - (4 + 7 w^{2})

7 7^{2}

- \frac{30}{- 6}

[(\frac{1}{2})^{3}]^{2}

What is (\sqrt[5]{xy^{-3}})x^{-1}y^{-2} ?
The solution to (\sqrt[5]{xy^{-3}})x^{-1}y^{-2} is 1/(\sqrt[5]{x^4)\sqrt[5]{y^3}y^2}