What is (4k+2)/(k^2-4)*(k-2)/(2k+1) ?

The solution to (4k+2)/(k^2-4)*(k-2)/(2k+1) is 2/(k+2)

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simplify (4k+2)/(k^2-4)*(k-2)/(2k+1)

simplify

\frac{4 k + 2}{k ^{2} - 4} \cdot \frac{k - 2}{2 k + 1}

\frac{2}{k + 2}

Solution steps

\frac{4 k + 2}{k ^{2} - 4} \cdot \frac{k - 2}{2 k + 1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 4 k + 2 ) ( k - 2 )}{( k ^{2} - 4 ) ( 2 k + 1 )}

Factor

4 k + 2 : 2 (2 k + 1)

= \frac{2 ( 2 k + 1 ) ( k - 2 )}{( k ^{2} - 4 ) ( 2 k + 1 )}

Cancel the common factor:

2 k + 1

= \frac{2 ( k - 2 )}{k ^{2} - 4}

Factor

k^{2} - 4 : (k + 2) (k - 2)

= \frac{2 ( k - 2 )}{( k + 2 ) ( k - 2 )}

Cancel the common factor:

k - 2

= \frac{2}{k + 2}

2 (s + 1)^{2} - 5 (s + 1) = 3

lo g_{3} (405) - lo g_{3} (5)

\frac{5 ^{3}}{5}

\frac{- 3}{13}

4 x^{2} - 24 = 0

What is (4k+2)/(k^2-4)*(k-2)/(2k+1) ?
The solution to (4k+2)/(k^2-4)*(k-2)/(2k+1) is 2/(k+2)