What is factor 6x^4+x^3+5x^2+x-1 ?

The solution to factor 6x^4+x^3+5x^2+x-1 is (2x+1)(3x-1)(x^2+1)

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factor 6x^4+x^3+5x^2+x-1

factor

6 x^{4} + x^{3} + 5 x^{2} + x - 1

(2 x + 1) (3 x - 1) (x^{2} + 1)

Solution steps

6 x^{4} + x^{3} + 5 x^{2} + x - 1

Use the rational root theorem

= (2 x + 1) \frac{6 x ^{4} + x ^{3} + 5 x ^{2} + x - 1}{2 x + 1}

\frac{6 x ^{4} + x ^{3} + 5 x ^{2} + x - 1}{2 x + 1} = 3 x^{3} - x^{2} + 3 x - 1

= (2 x + 1) (3 x^{3} - x^{2} + 3 x - 1)

Factor

3 x^{3} - x^{2} + 3 x - 1 : (3 x - 1) (x^{2} + 1)

= (2 x + 1) (3 x - 1) (x^{2} + 1)

- 4 (3 d - 2) - 7

\frac{1}{4} x^{2} - \frac{1}{2} ln (x)

12 x^{5} y^{4} (- 13 x^{4} y^{4})

ln (8) ln (16) ln (32)

+ 1 - 2

What is factor 6x^4+x^3+5x^2+x-1 ?
The solution to factor 6x^4+x^3+5x^2+x-1 is (2x+1)(3x-1)(x^2+1)