What is (6i)(7-7i)+(i)(1+3i) ?

The solution to (6i)(7-7i)+(i)(1+3i) is 39+43i

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simplify (6i)(7-7i)+(i)(1+3i)

simplify

(6 i) (7 - 7 i) + (i) (1 + 3 i)

39 + 43 i

Solution steps

(6 i) (7 - 7 i) + (i) (1 + 3 i)

Apply rule:

(a) = a

(i) = i

= 6 i (7 - 7 i) + i (1 + 3 i)

Expand

6 i (7 - 7 i) : 42 i + 42

= 42 i + 42 + i (1 + 3 i)

Expand

i (1 + 3 i) : i - 3

= 42 i + 42 + i - 3

Group like terms

= 42 i + i + 42 - 3

Add similar elements:

42 i + i = 43 i

= 43 i + 42 - 3

Subtract the numbers:

42 - 3 = 39

= 43 i + 39

Rewrite in standard complex form:

39 + 43 i

= 39 + 43 i

8 - 2 x + 5 x

(3 x^{2} + y^{3}) (5 x^{2} + 3 y^{3})

(1 0^{2})^{\frac{1}{3}}

(3 x - 1) (2 x - 10)

x - 2 x^{2}