What are the solutions to the equation (x+6)^2+12(x+6)+27=0 ?

The solutions to the equation (x+6)^2+12(x+6)+27=0 are x=-9,x=-15

Find the zeros of (x+6)^2+12(x+6)+27=0

The zeros of (x+6)^2+12(x+6)+27=0 are x=-9,x=-15

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(x + 6)^{2} + 12 (x + 6) + 27 = 0

x = - 9, x = - 15

Solution steps

(x + 6)^{2} + 12 (x + 6) + 27 = 0

Expand

(x + 6)^{2} + 12 (x + 6) + 27 : x^{2} + 24 x + 135

x^{2} + 24 x + 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 135}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot 135 = 6

x_{1, 2} = \frac{- 24 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 24 + 6}{2 \cdot 1}, x_{2} = \frac{- 24 - 6}{2 \cdot 1}

x = \frac{- 24 + 6}{2 \cdot 1} : - 9

x = \frac{- 24 - 6}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = - 9, x = - 15

\frac{1}{8} + \frac{3}{4}

12 5^{\frac{1}{2}} \cdot 5^{\frac{1}{2}}

b^{2} - b - 2 = 0

\frac{x}{6} - \frac{x - 4}{2} = 0

\frac{3 x + 6}{3} < 3

What are the solutions to the equation (x+6)^2+12(x+6)+27=0 ?
The solutions to the equation (x+6)^2+12(x+6)+27=0 are x=-9,x=-15
Find the zeros of (x+6)^2+12(x+6)+27=0
The zeros of (x+6)^2+12(x+6)+27=0 are x=-9,x=-15