What is expand (x-2)(x+3)(x-1) ?

The solution to expand (x-2)(x+3)(x-1) is x^3-7x+6

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expand (x-2)(x+3)(x-1)

expand

(x - 2) (x + 3) (x - 1)

x^{3} - 7 x + 6

Solution steps

(x - 2) (x + 3) (x - 1)

Expand

(x - 2) (x + 3) (x - 1) : (x^{2} + x - 6) (x - 1)

= (x^{2} + x - 6) (x - 1)

Distribute parentheses

= x^{2} x + x^{2} (- 1) + xx + x (- 1) - 6 x - 6 (- 1)

Simplify

x^{2} x + x^{2} (- 1) + xx + x (- 1) - 6 x - 6 (- 1) : x^{3} - 7 x + 6

= x^{3} - 7 x + 6

\frac{27 x ^{6} + 1}{3 x ^{2} + 1}

(a + 3) (a^{2} + 9) (a - 3)

\frac{2}{3} (3)^{\frac{3}{2}}

\frac{1}{a x} - \frac{1}{a ^{2} + a x} + \frac{1}{a + x}

\frac{x ^{2} + 2 x}{x ^{2} + 4 x + 4}

What is expand (x-2)(x+3)(x-1) ?
The solution to expand (x-2)(x+3)(x-1) is x^3-7x+6