What is (7/(r-5))/(\frac{26){3(r^3-5r^2)}} ?

The solution to (7/(r-5))/(\frac{26){3(r^3-5r^2)}} is (21r^2)/(26)

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simplify (7/(r-5))/(\frac{26){3(r^3-5r^2)}}

simplify

\frac{\frac{7}{r - 5}}{\frac{26}{3 ( r ^{3} - 5 r ^{2} )}}

\frac{21 r ^{2}}{26}

Solution steps

\frac{\frac{7}{r - 5}}{\frac{26}{3 ( r ^{3} - 5 r ^{2} )}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{7 \cdot 3 ( r ^{3} - 5 r ^{2} )}{( r - 5 ) \cdot 26}

Cancel

\frac{7 \cdot 3 ( r ^{3} - 5 r ^{2} )}{( r - 5 ) \cdot 26} : \frac{21 r ^{2}}{26}

= \frac{21 r ^{2}}{26}

20 x^{10} - 125

\frac{a ^{2}}{7 b} \cdot \frac{21 b ^{3}}{2 a ^{4}}

\frac{π}{3} \div 2

\frac{1}{5 x}

\frac{100}{150}

What is (7/(r-5))/(\frac{26){3(r^3-5r^2)}} ?
The solution to (7/(r-5))/(\frac{26){3(r^3-5r^2)}} is (21r^2)/(26)