What is (99w^3x^4-81x^2+63w)/(-9wx) ?

The solution to (99w^3x^4-81x^2+63w)/(-9wx) is -(11w^3x^4-9x^2+7w)/(wx)

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simplify (99w^3x^4-81x^2+63w)/(-9wx)

simplify

\frac{99 w ^{3} x ^{4} - 81 x ^{2} + 63 w}{- 9 w x}

- \frac{11 w ^{3} x ^{4} - 9 x ^{2} + 7 w}{w x}

Solution steps

\frac{99 w ^{3} x ^{4} - 81 x ^{2} + 63 w}{- 9 w x}

Factor

99 w^{3} x^{4} - 81 x^{2} + 63 w : 9 (11 w^{3} x^{4} - 9 x^{2} + 7 w)

= \frac{9 ( 11 w ^{3} x ^{4} - 9 x ^{2} + 7 w )}{- 9 w x}

Cancel the common factor:

9

= \frac{11 w ^{3} x ^{4} - 9 x ^{2} + 7 w}{- w x}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{11 w ^{3} x ^{4} - 9 x ^{2} + 7 w}{w x}

\frac{- 6}{2 ( 1 )}

x^{n} \cdot x

36 a^{2} - 60 ab + 25 b^{2}

What is (99w^3x^4-81x^2+63w)/(-9wx) ?
The solution to (99w^3x^4-81x^2+63w)/(-9wx) is -(11w^3x^4-9x^2+7w)/(wx)