What is (x^2-9)/(x^2-7x+12) ?

The solution to (x^2-9)/(x^2-7x+12) is (x+3)/(x-4)

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simplify (x^2-9)/(x^2-7x+12)

simplify

\frac{x ^{2} - 9}{x ^{2} - 7 x + 12}

\frac{x + 3}{x - 4}

Solution steps

\frac{x ^{2} - 9}{x ^{2} - 7 x + 12}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{2} - 7 x + 12}

Factor

x^{2} - 7 x + 12 : (x - 3) (x - 4)

= \frac{( x + 3 ) ( x - 3 )}{( x - 3 ) ( x - 4 )}

Cancel the common factor:

x - 3

= \frac{x + 3}{x - 4}

(a^{5})^{4}

\frac{x}{2} - 2

⌈ 3 ⌉

\frac{m}{m - 2} - \frac{2}{m - 2}

5 lo g_{2} (12)

What is (x^2-9)/(x^2-7x+12) ?
The solution to (x^2-9)/(x^2-7x+12) is (x+3)/(x-4)