What is 2(2-5t)+t^2(t-1)-(t^4-1) ?

The solution to 2(2-5t)+t^2(t-1)-(t^4-1) is -t^4+t^3-t^2-10t+5

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simplify 2(2-5t)+t^2(t-1)-(t^4-1)

simplify

2 (2 - 5 t) + t^{2} (t - 1) - (t^{4} - 1)

- t^{4} + t^{3} - t^{2} - 10 t + 5

Solution steps

2 (2 - 5 t) + t^{2} (t - 1) - (t^{4} - 1)

Apply the distributive law:

- (a - b) = - a + b

- (t^{4} - 1) = - t^{4} + 1

= 2 (2 - 5 t) + t^{2} (t - 1) - t^{4} + 1

Expand

2 (2 - 5 t) : 4 - 10 t

= 4 - 10 t + t^{2} (t - 1) - t^{4} + 1

Expand

t^{2} (t - 1) : t^{3} - t^{2}

= 4 - 10 t + t^{3} - t^{2} - t^{4} + 1

Group like terms

= - t^{4} + t^{3} - t^{2} - 10 t + 4 + 1

Add the numbers:

4 + 1 = 5

= - t^{4} + t^{3} - t^{2} - 10 t + 5

1 0^{- 3.8}

\frac{72 a ^{2 m} b ^{3 n}}{8 a ^{2 m} b ^{2 n}}

36 a^{2}

1 0^{- 5.2}

\frac{1}{2.145 \cdot 1 0 ^{- 3}}

What is 2(2-5t)+t^2(t-1)-(t^4-1) ?
The solution to 2(2-5t)+t^2(t-1)-(t^4-1) is -t^4+t^3-t^2-10t+5