What are the solutions to the equation (2x+3)(x+4)=0 ?

The solutions to the equation (2x+3)(x+4)=0 are x=-3/2 ,x=-4

Find the zeros of (2x+3)(x+4)=0

The zeros of (2x+3)(x+4)=0 are x=-3/2 ,x=-4

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(2 x + 3) (x + 4) = 0

x = - \frac{3}{2}, x = - 4

Solution steps

(2 x + 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x + 4 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 4

- 3

- 3 g + 6 = 9 g^{2}

\frac{y + 1}{4} - \frac{y}{3} > 1 + \frac{2 y - 1}{6}

7 x - 3 = 32

\frac{( x + 10 ) ^{5}}{( x + 10 ) ^{4}}

What are the solutions to the equation (2x+3)(x+4)=0 ?
The solutions to the equation (2x+3)(x+4)=0 are x=-3/2 ,x=-4
Find the zeros of (2x+3)(x+4)=0
The zeros of (2x+3)(x+4)=0 are x=-3/2 ,x=-4