What is (4x^4+4)/(x^2+1)-8/(x^2+1) ?

The solution to (4x^4+4)/(x^2+1)-8/(x^2+1) is 4x^2-4

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simplify (4x^4+4)/(x^2+1)-8/(x^2+1)

simplify

\frac{4 x ^{4} + 4}{x ^{2} + 1} - \frac{8}{x ^{2} + 1}

4 x^{2} - 4

Solution steps

\frac{4 x ^{4} + 4}{x ^{2} + 1} - \frac{8}{x ^{2} + 1}

Join

\frac{4 x ^{4} + 4}{x ^{2} + 1} - \frac{8}{x ^{2} + 1} : 4 (x + 1) (x - 1)

= 4 (x + 1) (x - 1)

Expand

4 (x + 1) (x - 1) : 4 x^{2} - 4

= 4 x^{2} - 4

- 1 + 2

\frac{- 9}{4}

\frac{π}{2} erfi (1)

\frac{- 2 x}{7} - \frac{- 3 x}{7}

What is (4x^4+4)/(x^2+1)-8/(x^2+1) ?
The solution to (4x^4+4)/(x^2+1)-8/(x^2+1) is 4x^2-4