What are the solutions to the equation x^2+4x=32 ?

The solutions to the equation x^2+4x=32 are x=4,x=-8

Find the zeros of x^2+4x=32

The zeros of x^2+4x=32 are x=4,x=-8

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x^{2} + 4 x = 32

x = 4, x = - 8

Solution steps

x^{2} + 4 x = 32

Move

32

to the left side

x^{2} + 4 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 32) = 12

x_{1, 2} = \frac{- 4 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 12}{2 \cdot 1}, x_{2} = \frac{- 4 - 12}{2 \cdot 1}

x = \frac{- 4 + 12}{2 \cdot 1} : 4

x = \frac{- 4 - 12}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 4, x = - 8

(4^{- 1})^{2}

\frac{2}{4} + \frac{1}{2}

4 - x^{2} = 2 x + 1

(\frac{3 x ^{2}}{8})^{2}

10 a^{3} + 4 a^{2} + 5 a + 2

What are the solutions to the equation x^2+4x=32 ?
The solutions to the equation x^2+4x=32 are x=4,x=-8
Find the zeros of x^2+4x=32
The zeros of x^2+4x=32 are x=4,x=-8